print star triangle

Program 1 

C++ LANGUAGE

#include<iostream.h>     
#include<conio.h>
void main()
{
int n;
clrscr();
cout<<"Enter Number Of Lines You want";
cin>>n;
cout<<endl;
for (int i=0; i<n; i++)
{
for (int j=i; j>=0; j--)
{
cout<<"*";
}
cout<<"\n";
}
 getch();
}

C LANGUAGE

• #include<conio.h>
  void main()
  {
  clrscr();
  for(int i=0;i<5;i++)
  {
  for(int j=i;j>=0;j--)
  {
  printf("*");
  }
  printf("\n");
  }
  getch();
  }

OUTPUT :- 

Program 2

#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
for(int i=0;i<5;i++)
{
for(int j=i;j>=0;j--)
{
printf("%d",i+1);
}
printf("\n");
}
getch();

}

OUTPUT :-

PROGRAM 3

#include<stdio.h>

#include<conio.h>

void main()

{

clrscr();

int k=5;

for(int i=0;i<5;i++)

{

for(int j=i;j>=0;j--)

{

printf("%d",k);

}

k--;

printf("\n");

}

getch();

}

Program 4

#include<stdio.h>

#include<conio.h>

void main()

{

int k=5;

for(int i=0;i<5;i++)

{

for(int j=i;j>=0;j--)

{

printf("%d",k); 

}

k--;

printf("\n");

}

getch();

}

EXPLANATION 

1. At first k=5 and j loop runs one time as j=i ; j>=0

so it prints 5

now k--; so k=4

2. Secondly k=4 j loop runs two time as j=i (i is 1) ; j>=0

so it prints 44

Now k--; so k=3

3. thirdly k=3 j loop runs three times j=i (i is 2) ; j>=0 

so it prints 333

Now k--; so k=2 

4. fourthly k=2 j loop runs four times j=i (i is 3) ; j>=0 

so it prints 444

Now k--; so k=1

5. Fifthly k=1 j loop runs five times j=i (i is 4) ; j>=0 

so it prints 5555

Now k--; so k=0  

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heemanshu bhalla