Write A Program To Add Two Numbers Without Using Addition Operator

Case 1: For only Positive Numbers

# include < iostream.h >
# include < conio.h >


void main ( )
{
int Num1,Num2,Num3,Num4;
Cout<<"Enter First Number:- ";
Cin>>Num1;
Num4 = Num1;
Cout<<"Enter Second Number:- ";
Cin>>Num2;

While ( Num2 >0 )
{
Num1++;
Num2--;
}
Cout<<"Addition of "<<Num4<<" And "<<Num2<<"is :- "<<Num1;
getch ( ) ;
}

OUTPUT :- 

Case 2 : If Only Second Number is Negative

# include < iostream.h >
# include < conio.h >

void main ( )
{
int Num1,Num2,Num3,Num4;
Cout<<"Enter First Number:- ";
Cin>>Num1;
Num4 = Num1;
Cout<<"Enter Second Number:- ";
Cin>>Num2;

While ( Num2 <0 )
{
Num1--;
Num2++;
}
Cout<<"Addition of "<<Num4<<" And "<<Num2<<"is :- "<<Num1;
getch ( ) ;
}

OUTPUT :-

Case 3: If only First Number is Negative 

# include < iostream.h >
# include < conio.h >

void main ( )
{
int Num1,Num2,Num3,Num4;
Cout<<"Enter First Number:- ";
Cin>>Num1;
Num4 = Num1;
Cout<<"Enter Second Number:- ";
Cin>>Num2;

While ( Num2 > 0 )
{
Num1++;
Num2--;
}
Cout<<"Addition of "<<Num4<<" And "<<Num2<<"is :- "<<Num1;
getch ( ) ;
}

OUTPUT :- 



Case 4 : If First And Second Number Both Are Negative

#include<iostream.h>

#include<conio.h>

main()

{

int a,b,d;

cout<<"Enter First Number:-  ";

cin>>a;

d=a

cout<<"Enter First Number:- ";

cin>>b;

if ((a>0) && (b>0))

{

while(b>0)

{

a++;

b--;

}

}

if ((a<0) && (b<0))

{

while(b<0)

{

a--;

b++;

}

}

 if(a<0)

 {

while(b>0)

   {

 a++;

 b--;

  }

  }

    if (b<0)

    {

while (b<0)

  {

 b++;

 a--;

 }

 }

Cout<<"Addition of "<<d<<" And "<<b<<"is :- "<<a;

getch();

}

Four Possible Output Combinations 

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heemanshu bhalla